1296=-16t^2+288t

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Solution for 1296=-16t^2+288t equation: 



1296=-16t^2+288t

We move all terms to the left:

1296-(-16t^2+288t)=0

We get rid of parentheses

16t^2-288t+1296=0

a = 16; b = -288; c = +1296;
Δ = b2-4ac
Δ = -2882-4·16·1296
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$t=\frac{-b}{2a}=\frac{288}{32}=9$

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